\[ 1\text{ cent}\times\left ( \frac{30\frac{\text{miles}}{\text{gallon}}} {\frac{2.73\text{ grams}}{50\text{ pounds}}\times0.5\%\times\frac{\$3.50}{\text{gallon}}} \right )\approx140,000\text{ miles} \]
\[ \frac{70\text{ kg}\cdot\text{si\k{l}a ciążenia}\cdot50\text{ centimeters}}{20\%}=1.72\text{ kJ}=0.41\text{ kilokalorii} \]
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